In a double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then, in the interference pattern [JEE' 2000 (Screening), 1/35]
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In interference we know that
Ι max = 
and Ι min = 
Under normal conditions (when the widths of both the slits are equal)
Ι 1 ≈ Ι 2 = Ι (say)
∴ Ι max = 4 Ι and Ι min = 0
When the width of one of the slits is increased. Intensity due to that slit would increase, while that of the other will remain same. So let :
Ι 1 = Ι and Ι 2 = η Ι ( η > 1)
Then Ι max = Ι 
> 4 Ι and Ι min = Ι 
< 0
∴ Intensity of both maximum and minima is increased.
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